Wien's Law Calculator (Peak Wavelength from Temperature)

Wien's displacement law says the wavelength at which a black body radiates most strongly is inversely proportional to its absolute temperature. This Wien's law calculator gives the peak wavelength and peak frequency for any temperature, and solves backwards to estimate temperature from the colour of a star or a glowing object.

nm
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µm
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THz
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Type in any field to change it. Press × on a value to calculate that field instead.

How to use the Wien’s law calculator

Enter the temperature of the radiating body (switch the unit to °C or °F if you prefer). The calculator returns the peak wavelength in nanometres and micrometres and the peak frequency of the spectrum. To estimate a temperature, enter the peak wavelength and clear the temperature field.

Wien’s displacement law formula

λmax = b ÷ T  ·  b = 2.897771955 × 10⁻³ m·K

νmax = 5.878925757 × 10¹⁰ Hz/K × T

Example

The Sun’s photosphere is about 5,778 K:

  • λmax = 2.897772 × 10⁻³ ÷ 5778 = 501.5 nm (blue-green light)
  • νmax = 5.879 × 10¹⁰ × 5778 = 339.7 THz — a wavelength of 883 nm in the per-frequency spectrum

Peak wavelength of common sources

Source Temperature Peak wavelength Band
Liquid nitrogen 77 K 37,633 nm (37.6 µm) Infrared
Ice / water at 0 °C 273 K 10,609 nm (10.6 µm) Infrared
Human body 310 K 9,343 nm (9.34 µm) Infrared
Boiling water 373 K 7,766 nm (7.77 µm) Infrared
Red-hot iron 1,000 K 2,898 nm (2.9 µm) Near infrared
Incandescent filament 2,800 K 1,035 nm (1.03 µm) Near infrared
Red dwarf star 3,200 K 906 nm (0.906 µm) Near infrared
Sun (photosphere) 5,778 K 502 nm (0.502 µm) Visible
Sirius A 9,940 K 292 nm (0.292 µm) Ultraviolet

Notes

  • Only ideal black bodies follow the law exactly; real surfaces have emissivity below 1, but their peak position is usually close.
  • The total power radiated rises with T⁴ — see the Stefan–Boltzmann law calculator.
  • To convert the peak wavelength to photon energy, use the photon energy calculator.

Frequently asked questions

What is Wien's displacement law?

λ_max = b ÷ T, with b = 2.897771955 × 10⁻³ m·K. A body at 5,778 K (the Sun) peaks at about 501 nm; one at 310 K (a person) peaks at about 9.3 µm in the infrared.

How do I find a star's temperature from its peak wavelength?

T = b ÷ λ_max. Enter the peak wavelength in nanometres and clear the temperature field — a peak at 290 nm means about 10,000 K.

Why don't the peak wavelength and peak frequency match?

They describe the spectrum per unit wavelength and per unit frequency, which have different shapes. The frequency peak, ν_max = 5.879 × 10¹⁰ Hz/K × T, corresponds to a wavelength about 1.76 times longer than λ_max.

Why do infrared thermometers work at 8–14 µm?

Objects near room temperature radiate most strongly around 10 µm, and the atmosphere is transparent in the 8–14 µm window.

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