Ferranti Effect Calculator (Receiving-End Voltage Rise)

On a long, lightly loaded transmission line the charging current flowing through the line inductance makes the receiving-end voltage rise above the sending-end voltage. This Ferranti effect calculator uses the lossless-line equation Vr = Vs ÷ cos(βl) to find that rise — see the Ferranti effect in transmission lines.
How to use the Ferranti effect calculator
Enter the sending-end voltage, the line length, the line’s inductance and capacitance per km and the frequency. The calculator returns the line’s electrical length, the open-circuit receiving-end voltage and the percentage rise. Typical overhead-line values are about 1.0 mH/km and 11–12 nF/km; cables have much higher capacitance.
Ferranti effect formula
β = 2πf √(LC) · Vr = Vs ÷ cos(βl)
Worked example
A 400 kV, 300 km, 50 Hz overhead line with L = 1.0 mH/km and C = 11.5 nF/km, open at the far end:
- β = 2π × 50 × √(1.0×10⁻⁶ × 11.5×10⁻¹²) = 1.0654e-03 rad/km
- βl = 0.3196 rad (18.31°)
- Vr = 400 ÷ cos(0.3196) = 421.3 kV — a 5.33% rise
Ferranti rise vs line length (400 kV, 1.0 mH/km, 11.5 nF/km, 50 Hz)
| Length | Vr ÷ Vs | Rise | Vr |
|---|---|---|---|
| 50 km | 1.0014 | 0.14% | 400.6 kV |
| 100 km | 1.0057 | 0.57% | 402.3 kV |
| 200 km | 1.0231 | 2.31% | 409.3 kV |
| 300 km | 1.0533 | 5.33% | 421.3 kV |
| 400 km | 1.0982 | 9.82% | 439.3 kV |
| 500 km | 1.1608 | 16.08% | 464.3 kV |
| 800 km | 1.5192 | 51.92% | 607.7 kV |
Notes
- The lossless model slightly overstates the rise; line resistance and any load reduce it.
- Underground cables show the effect over much shorter distances because their capacitance is 20–50 times higher.
Frequently asked questions
What is the Ferranti effect?
The rise of receiving-end voltage above sending-end voltage on a long line at light load or no load. The line's shunt capacitance draws a leading charging current, and its flow through the series inductance raises the voltage along the line.
What is the Ferranti effect formula?
For a lossless line on open circuit, Vr = Vs ÷ cos(βl), with β = ω√(LC). A useful approximation is Vr ≈ Vs × (1 + ω²LC·l² ÷ 2).
How big is the Ferranti rise?
For a 50 Hz overhead line it is roughly 0.5% at 100 km, 5% at 300 km and about 15% at 500 km.
How is the Ferranti effect controlled?
With shunt reactors at the line ends (switched in at light load), SVCs or STATCOMs, and by energising long lines from the stronger end.
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