Inclined Plane Calculator (Forces, Friction & Acceleration)

On a slope, gravity splits into a component pulling the object down the incline and a component pressing it into the surface, which sets the friction. This inclined plane calculator resolves those forces and gives the acceleration of a sliding object and the force needed to push it up at steady speed.

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Type in any field to change it. Press × on a value to calculate that field instead.

How to use the inclined plane calculator

Enter the mass, the angle of the slope and the coefficient of friction (use 0 for a frictionless slope). You get the gravity component along the slope, the normal force, the friction force, the acceleration of a sliding object and the force needed to push it up the slope at constant speed.

Inclined plane formulas

F∥ = m g sin θ  ·  N = m g cos θ  ·  Ff = μ N

a = g (sin θ − μ cos θ)  ·  Fup = m g (sin θ + μ cos θ)

Example

A 10 kg block on a 30° slope with μ = 0.2:

  • F∥ = 10 × 9.807 × 0.5 = 49.03 N
  • N = 10 × 9.807 × 0.866 = 84.93 N, friction = 16.99 N
  • a = 9.807 × (0.5 − 0.2 × 0.866) = 3.205 m/s² down the slope
  • Push up at constant speed = 66.02 N

Acceleration by angle (m/s²)

Angle No friction μ = 0.2
5° 0.855 -1.099
10° 1.703 -0.229
15° 2.538 0.644
20° 3.354 1.511
30° 4.903 3.205
45° 6.934 5.547
60° 8.493 7.512

Negative values mean friction prevents sliding.

Frequently asked questions

What is the acceleration down an inclined plane?

a = g (sin θ − μ cos θ). Without friction it is simply g sin θ — about 4.9 m/s² on a 30° slope.

What does a negative acceleration mean?

Friction is larger than the pull down the slope, so a block at rest will not start sliding (if μ is the static coefficient) and a sliding block slows down.

At what angle will an object start to slide?

When tan θ exceeds the static coefficient of friction — the angle of repose θ = arctan μs. For μs = 0.5 that is about 26.6°.

How much force is needed to push a load up a ramp?

F = m g (sin θ + μ cos θ) at steady speed, ignoring acceleration. A shallower ramp needs less force but a longer distance.

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