Parallel Plate Capacitor Calculator (C = ε₀εrA/d)
Two conducting plates separated by an insulator form a capacitor whose value depends only on the plate area, the gap and the permittivity of the material between them. This parallel plate capacitor calculator gives the capacitance, charge, stored energy and electric field — see what capacitance is, and how the same principle is used in capacitance level measurement.
How to use the parallel plate capacitor calculator
Enter the dielectric constant of the material between the plates (1 for air), the overlapping plate area, the separation and the applied voltage. The calculator returns the capacitance, the charge on each plate, the stored energy and the electric field in the gap. To design for a target value, enter the capacitance and clear the area or the gap.
Parallel plate capacitor formulas
C = ε0 εr A ÷ d · Q = C V · W = ½ C V² · E = V ÷ d
ε0 = 8.8541878128 × 10⁻¹² F/m.
Example
Two 100 cm² plates 1 mm apart in air, charged to 100 V:
- C = 8.854 × 10⁻¹² × 1 × 0.01 ÷ 0.001 = 88.54 pF
- Q = 88.54 pF × 100 V = 8.854 nC
- W = ½ × 88.54 pF × 100² = 0.4427 µJ
- E = 100 V ÷ 1 mm = 0.1 kV/mm — well below air’s breakdown of about 3 kV/mm
Capacitance with different dielectrics
Same plates as the example (100 cm², 1 mm gap):
| Dielectric | εr | Capacitance |
|---|---|---|
| Vacuum / air | 1 | 88.5 pF |
| PTFE (Teflon) | 2.1 | 185.9 pF |
| Polypropylene | 2.2 | 194.8 pF |
| Paper (dry) | 3.5 | 309.9 pF |
| FR-4 PCB laminate | 4.4 | 389.6 pF |
| Glass | 6 | 531.3 pF |
| Mica | 6.5 | 575.5 pF |
| Water (20 °C) | 80 | 7,083.4 pF |
Dielectric constants are typical values; they vary with frequency, temperature and grade.
Applications
- Capacitive level probes measure the change in capacitance as a liquid with higher εr replaces air between a probe and the tank wall.
- Touch sensors and proximity switches detect the extra capacitance of a finger or object.
- PCB planes: a power–ground plane pair 0.2 mm apart in FR-4 gives about 19 pF per cm².
Frequently asked questions
What is the formula for a parallel plate capacitor?
C = ε₀ εr A ÷ d, with ε₀ = 8.854 × 10⁻¹² F/m, A the overlapping plate area in m² and d the gap in metres. 100 cm² plates 1 mm apart in air give 88.5 pF.
How does the dielectric change the capacitance?
Capacitance is multiplied by the relative permittivity εr. Filling the same gap with FR-4 (εr ≈ 4.4) gives about 390 pF instead of 88.5 pF.
What limits the voltage of a capacitor?
The dielectric strength. Dry air breaks down at about 3 kV/mm, so a 1 mm air gap arcs at around 3 kV; good film dielectrics withstand hundreds of kV/mm.
Does the formula include fringing?
No. It assumes the gap is small compared with the plate size. Fringing fields at the edges add a little extra capacitance when the gap is not small.